Chemistry, asked by lakshyakhandelwal100, 6 hours ago

When you have mixed the solutions of lead(II) nitrate and potassium iodide,

(i) what was the colour of the precipitate formed and can you name the precipitate?

(ii) write the balanced chemical equation for this reaction.

(iii) is this also a double displacement reaction?​

Answers

Answered by ITZRWLove
4

Hey mate !!

Here is ur Answer ⤵️

1) what was the colour of the precipitate formed and can you name the precipitate?

Ans - The lead halides are insoluble in water, so lead iodide will be precipitated. So, the name of the compound precipitated is lead iodide and it is a yellow colour precipitate.

2) write the balanced chemical equation for this reaction ?

Ans - 1: Balancing Chemical Equations :

* N2+O2→N2O5(unbalanced) N 2 + O 2 → N 2 O 5 (unbalanced)

* N2+5O2→2N2O5(unbalanced) N 2 + 5 O 2 → 2 N 2 O 5 (unbalanced)

* 2N2+5O2→2N2O5 2 N 2 + 5 O 2 → 2 N 2 O 5.

3) is this also a double displacement reaction?

Ans - A double displacement reaction is a type of chemical reaction in which the reactant ions exchange places to form new products. ... A double displacement reaction is also called a double replacement reaction, salt metathesis reaction, or double decomposition.

Hope it helps you ✔️

Thank you ❣️

@ItRWlove

Answered by Anonymous
9

Answer:

  1. The precipitate is yellow in colour and the compound is lead (II) Iodide.
  2. Pb (NO3)2(aq) + 2KI(aq) → PbI2(s) + 2KNO3(aq).
  3. Yes, it is a double displacement reaction.
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