Question

When you sneeze, the air in your lungs accelerates from rest to 160 km/h in approximately 0.5 seconds. What is the acceleration in ms^-2?

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Answer 1

Explanation:

Change in velocity, Δv = 160 km/hr Change in time, Δt = 0.55 s Note that 1 km = 1000 m 1 h = 3600 s Therefore Δv = (160,000 m/h)*(1/3600 h/s) = 44.4444 m/s By definition, the acceleration is a = Δv/Δt = (44.4444 m/s)/(0.55 s) = 80.808 m/s²

Change in velocity, Δv = 160 km/hr Change in time, Δt = 0.55 s Note that 1 km = 1000 m 1 h = 3600 s Therefore Δv = (160,000 m/h)*(1/3600 h/s) = 44.4444 m/s By definition, the acceleration is a = Δv/Δt = (44.4444 m/s)/(0.55 s) = 80.808 m/s²