Chemistry, asked by sushmita200325, 1 year ago

When ZnS is boiled with strong nitric acid, the products
are zinc nitrate, sulphuric acid and nitrogen dioxide.
What are the changes in the oxidation numbers of Zn,
S and N:
(A)+2, +4,-1 (B)+2, +6,-2
(C)0, +4,-2
(D) 0,+8,-1​

Answers

Answered by UsmanSant
5

Answer:

When ZnS reacts with strong nitric acid the products are zinc nitrate, sulphuric acid and nitrogen dioxide. The changes in the oxidation state of zinc, sulfur and nitrogen are +2, 6 and -2.

Explanation:

These changes occur in the oxidation state of the atoms zinc, sulfur and nitrogen because concentrated nitric acid is a strong oxidizing agent.

Answered by rajeshmanderna
2

Answer:

Explanation:

(D)0,+8,-1

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