where does majority of the absorption process during digestion take place?
Answers
Answer:
the small intestine
Explanation:
Digestion begins in the mouth and continues as food travels through the small intestine. Most absorption occurs in the small intestine.
Answer:
Let assume that first term and common difference of an AP is a and d respectively.
According to statement, it is given that 7 times the 7^{th}7th term of an AP is equals to 11 times the 11^{th}11th term of an AP.
So,
\begin{gathered}\rm \: 7a_7 \: = \: 11a_{11} \\ \end{gathered}7a7=11a11
Wᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ,
↝ nᵗʰ term of an arithmetic progression is,
\begin{gathered}\begin{gathered}\red\bigstar\:\:{\underline{\orange{\boxed{\bf{\green{a_n\:=\:a\:+\:(n\:-\:1)\:d}}}}}} \\ \end{gathered}\end{gathered}★an=a+(n−1)d
Wʜᴇʀᴇ,
aₙ is the nᵗʰ term.
a is the first term of the progression.
n is the no. of terms.
d is the common difference.
Tʜᴜs,
\begin{gathered}\rm \: 7[a + (7 - 1)d] \: = \: 11[a + (11 - 1)d] \\ \end{gathered}7[a+(7−1)d]=11[a+(11−1)d]
\begin{gathered}\rm \: 7(a + 6d) = 11(a + 10d) \\ \end{gathered}7(a+6d)=11(a+10d)
\begin{gathered}\rm \: 7a + 42d = 11a + 110d \\ \end{gathered}7a+42d=11a+110d
\begin{gathered}\rm \: 11a + 110d - 7a - 42d = 0 \\ \end{gathered}11a+110d−7a−42d=0
\begin{gathered}\rm \: 4a + 68d = 0 \\ \end{gathered}4a+68d=0
\begin{gathered}\rm \: 4(a + 17d) = 0 \\ \end{gathered}4(a+17d)=0
\begin{gathered}\rm \: a + 17d = 0 \\ \end{gathered}a+17d=0
\begin{gathered}\rm \: a + (18 - 1)d = 0 \\ \end{gathered}a+(18−1)d=0
\begin{gathered}\bf\implies \:a_{18} \: = \: 0 \\ \end{gathered}⟹a18=0
Hence, Proved
\rule{190pt}{2pt}
Additional Information :-
↝ Sum of n terms of an arithmetic progression is,
\begin{gathered}\begin{gathered}\red\bigstar\:\:{\underline{\orange{\boxed{\bf{\green{S_n\:=\dfrac{n}{2} \bigg(2 \:a\:+\:(n\:-\:1)\:d \bigg)}}}}}} \\ \end{gathered}\end{gathered}★Sn=2n(2a+(n−1)d)
Wʜᴇʀᴇ,
Sₙ is the sum of n terms of AP.
a is the first term of the progression.
n is the no. of terms.
d is the common difference.