where e is the magnitude of charge of electron. Assuming
If potential energy of an electron and a proton in a hypothetical situation is given by U--
Bohr's model to be applicable, the radius of oth Bohr's orbit is
Answers
Answered by
2
Q -> If potential energy between a proton and an electron is given by ∣U∣=ke²/2R³ , where e is the charge of electron and R is the radius of atom, then radius of Bohr's orbit is given by (h = Planck's constant, k = constant)
given, potential energy, |U| = ke²/2R³
differentiating with respect to R,
d|U|/dR = -3ke²/2R⁴
we know, F = -dU/dR
so, F = 3Ke²/2R⁴
from Bohr's model of atom,
centripetal force is balanced by electrostatic force.
so, F = 3Ke²/2R⁴ = mv²/R .........(1)
from Bohr's postulation , mvR = nh/2π
v = nh/2πmR ...,...(2)
from equations (1) and (2) we get,
3Ke²/2R⁴ = m(nh/2πmR)²/R
⇒3Ke²/2R⁴ = n²h²/4π²mR³
⇒6Ke²π²m/R = n²h²
⇒R = 6Ke²π²m/n²h²
therefore radius of nth Bohr's orbit is 6Ke²π²m/n²h²
Similar questions