Question

where is in the shape of a square of side 10 cm if the wire is bent into a rectangle of 12 cm find its breadth which encloses an area of square or rectangle​

Answer 1

Answer:

perimeter of square4a=4x10=40cm

Perimeter of rectangle = 2 (I + b)

2(l+b) = 40

2I+2b=40

I=12

24+2b=40

2b = 16, b = 8

area of rectangle = Ixb = 12x8=96

=96cm2

Answer 2

Answer:

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Step-by-step explanation:

Side of the square = 10 cm

Length of the wire = Perimeter of the square

= 4 x side

= 4 x 10cm

= 40 cm

Length of the rectangle, l = 12 cm. Let b be the breadth of the rectangle.

Perimeter of rectangle Length of wire = 40 cm

Perimeter of the rectangle = 2 (l + b)

40 = 2 (12 + b)

(OR) 40 / 2 = 12 + b

b = 20 - 12 = 8 cm

Therefore,The breadth of the rectangle is 8 cm.

Area of the square = (side)²

= 10 cm × 10 cm = 100cm²

Area of the rectangle = l × b

= 12cm × 8cm = 96cm²

So , the square encloses more area even though its perimeter is the same as that of the rectangle.