Physics, asked by keerthi289884, 5 months ago

Where should an object be place from a converging lens of focal length 20cm, so as to obtain a real magnified image?

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Answered by Anonymous
120

\huge{\bf{\green{\mathfrak{Question:-}}}}

  • Where should an object be placed from a converging lens of focal length 20cm, so as to obtain a real magnified image.

\huge {\bf{\orange{\mathfrak{Answer:-}}}}

\bullet{\leadsto} \: \textsf{According to the question,}

\bullet{\leadsto} \: \textsf{\underline{Converging lens means Convex lens.}}

\bullet{\leadsto} \: \textsf{To obtain a real and magnified image,}

\bullet{\leadsto} \: \textsf{\underline{We have to place it between F and C.}}

\bullet{\leadsto} \: \textsf{F = 20 cm.}

\bullet{\leadsto} \: \textsf{C = ?}

\bullet{\leadsto} \: \sf C \: = \: 2f

\bullet{\leadsto} \: \sf C \: = \: 2 \: * \: 20

\bullet{\leadsto} \: \boxed{\sf C \: = \: 40 \: cm.}

\bullet{\leadsto} \: \textsf{In between F and C means,}

\bullet{\leadsto} \: The object must be placed between 20 cm (F) and 40 cm (C).

\huge{\bf{\purple{\mathfrak{Note :-}}}}

\bullet{\leadsto} \: \boxed{\textsf{See Attachment}}

\bullet \: \textsf{Then,}

\large\bullet \:\boxed{ \textsf{Characteristics of Image :-}}

\sf{Object \: placed \: :- \: Between \: F_{2} \: and \: C_{2}.}

\textsf{It is a real image.}

\textsf{It is inverted.}

\sf{Image \: formed \: :-\: Beyond \: C_{1}.}

\textsf{Object size < Image size i.e it is magnified.}

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