where should an object be placed in front of a concave mirror of focal length 20 cm so as to obtain a two times magnified real image
Answers
Answered by
389
Since it is 2 times magnified, m = -2
so -v/u = -2
similarly, 1/v + 1/u = 1/f
so 1/v + 1/u = 1/-20
-v/v + -v/u = -v/-20 (multiply throughout by -v)
-1 -2 = v/20
-3 = v/20
v = -60
-2 = -v/u
-2 = 60/u
u = -30
so the object must be placed 30 cm from the mirror.
so -v/u = -2
similarly, 1/v + 1/u = 1/f
so 1/v + 1/u = 1/-20
-v/v + -v/u = -v/-20 (multiply throughout by -v)
-1 -2 = v/20
-3 = v/20
v = -60
-2 = -v/u
-2 = 60/u
u = -30
so the object must be placed 30 cm from the mirror.
Róunak:
yup
Answered by
205
heya friends.!!
focal length "f"=-20
magnification "m"=-2times.
as you know that
magnification =f/f-u by using mirror formula obtain relation between m and f. -
so using this formula,
-2=-20/-20-u
40+2u=-20.
u=-60/2
u=-30cm
u " distance of object =- -30cm
so if you object be placed at the distance of 30 cm then the two times magnified image will be obtain.
hope it help you.
☺
@rajukumar☺
focal length "f"=-20
magnification "m"=-2times.
as you know that
magnification =f/f-u by using mirror formula obtain relation between m and f. -
so using this formula,
-2=-20/-20-u
40+2u=-20.
u=-60/2
u=-30cm
u " distance of object =- -30cm
so if you object be placed at the distance of 30 cm then the two times magnified image will be obtain.
hope it help you.
☺
@rajukumar☺
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