where should an object be placed in front of a concave mirror of focal length 20 cm so as to obtain a two times magnified real image?
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Hey mate
Here is your answer
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30 cm before the lens
Magnification M =-2 ( real and inverted image)
M = v / u =-2
V=-2u ....eq (1)
From lens formula
1/f = 1/v - 1/u .....eq (2)
Given f = 20cm
On substitution of eq (1) in (2) we get U = - 30 cm ( it is negative from the sign convention)
Hope it helps
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Here is your answer
---------------------------------------------
30 cm before the lens
Magnification M =-2 ( real and inverted image)
M = v / u =-2
V=-2u ....eq (1)
From lens formula
1/f = 1/v - 1/u .....eq (2)
Given f = 20cm
On substitution of eq (1) in (2) we get U = - 30 cm ( it is negative from the sign convention)
Hope it helps
Please mark as Brainliest
reetamehta06pd593x:
what do you mean by that
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