Where should you place an object in front of a converging mirror in order to get an image of same size as that of the object? Explain the same with a neat ray diagram. Write the nature of this image formed
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Answer:
at the centre of curvature
Explanation:
- Draw an object at the centre of curvature of the converging or concave mirror. draw 1 lines from the tip of the object to the surface of the concave mirror such that those lines are parallel to the principal axis. The reflected ray of this incident ray will pas through the focus of the mirror.
- Draw another ray such that it originates from the top tip of the object and passes through the focus. The reflected ray will be parallel to the and will be below the principal axis.
- The reflected rays from cases 1 and 2 will meet at a point below 'C' such that the distance between the point of intersection and the place where the object was kept (centre of curvature) will be equal and it will be a real and inverted image of the same size.
- this proves that when an object is placed at centre of curvature, the image will be formed at centre of curvature and will be real, inverted and of the same size.
- One can also cast this image on a screen as it is a real image.
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