where the graph of the linear equation 4x-3y=12 cuts y axis
Answers
Answered by
17
Answer: (0,-4)
Step-by-step explanation: Subtract 4x from both sides, then divide both sides by 3, then divide by the negative (-1) and you are left with y=4/3x-4
The y intercept is -4
Answered by
9
Step-by-step explanation:
Answer is (0,-4)
4x= 12 + 3y
Let x=0 and y = -4
So,
4(0) = 12 + 3(-4)
0 = 12 + (-12)
0 = 0
Hence (0,-4) is a solution of equation 4x-3y=12 which cuts at y axis.
Hope u guys like it
please give me thousands of likes
please mark me as Brainlist
Similar questions