where will the hand of a clock stop if it starts at 4 and makes 3 by 4 of a revolution clockwise?
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Step-by-step explanation:
a clock is a circle of 360°
3/4 * 360 = 270 °
there are 12 demarkation on a clock
degrees between each demarkation =
1/12 * 360
30
demarkations crossed in 270°
270 /30
9
the hands started at 4 and hence will stop at 9+4 = 13
demarkations = 12
no . of demarkation crossed after crossing 12th demarkation =
13-12 = 1
it will stop at 1
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