Math, asked by deepikakeswani, 2 months ago

where will the hand of a clock stop if kavya starts form 5 and makes ¾ of a rotation anti clock wise​

Answers

Answered by ridhiahuja645
5

Answer:

At 8

Step-by-step explanation:

3/4 revolution means angle of 270°

As angle between two consecutive no. on clock is 30° . When we move anti clockwise from 5 , we count angle of 30° between each of them. Angle of 270° is made at 8 .

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Answered by Anonymous
1

Question :-

where will the hand of a clock stop if kavya starts from 5 and make 3/4 of a rotation anti clock wise ?

Solution :-

we know that

1 rotation = 360° .

so,

→ (3/4) of rotation = (3/4) * 360° = 270° .

then,

→ 5 + 270° (anticlockwise)

→ 5 + {(180° + 90°)anticlockwise}

→ (5 + 180° anticlockwise) + 90° anticlockwise

→ 11 (opposite) + 90° anticlockwise

→ 11 + 90° anticlockwise

→ 11 + 3*30° anticlockwise

→ 11 - 3

→ 8 (Ans.)

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