Question

Where will the hand of a clock stop if kavya starts from 5 and makes ¾ of a rotation

anti-clock wise?​

Answer 1

Question :- where will the hand of a clock stop if kavya starts from 5 and make 3/4 of a rotation anti clock wise ?

Solution :-

we know that,

1 rotation = 360° .

so,

→ (3/4) of rotation = (3/4) * 360° = 270° .

then,

→ 5 + 270° (anticlockwise)

→ 5 + {(180° + 90°)anticlockwise}

→ (5 + 180° anticlockwise) + 90° anticlockwise

→ 11 (opposite) + 90° anticlockwise

→ 11 + 90° anticlockwise

→ 11 + 3*30° anticlockwise

→ 11 - 3

→ 8 (Ans.)

Hence, the hand of a clock stop will stop at 8 .

Learn more :-

सोहन के घर से निकलते समय, घड़ी में घंटे की सुई 5 और 6 बजे के बीच और मिनट की सुई 6 और7बजे के बीच थी। यदि, लगभग एक घंटे बा...

https://brainly.in/question/29299343

*घड़ी में क्या समय होगा, यदि दिया गया है कि घड़ी की दोनों सुइयों के बीच बना कोण अधिक कोण है?*

1️⃣ 1:10

2️⃣ 4:25

3️⃣ 5:50

...

https://brainly.in/question/25996383

Answer 2

Question :-

where will the hand of a clock stop if kavya starts from 5 and make 3/4 of a rotation anti clock wise ?

Solution :-

we know that

1 rotation = 360° .

so,

→ (3/4) of rotation = (3/4) * 360° = 270° .

then,

→ 5 + 270° (anticlockwise)

→ 5 + {(180° + 90°)anticlockwise}

→ (5 + 180° anticlockwise) + 90° anticlockwise

→ 11 (opposite) + 90° anticlockwise

→ 11 + 90° anticlockwise

→ 11 + 3*30° anticlockwise

→ 11 - 3

→ 8 (Ans.)