Question

where will the hand of a clock stop if Kavya starts from 5 and makes 3/4 of a rotation anticlockwise.​

Answer 1

Question :-

where will the hand of a clock stop if kavya starts from 5 and make 3/4 of a rotation anti clock wise ?

Solution :-

we know that,

1 rotation = 360° .

so,

→ (3/4) of rotation = (3/4) * 360° = 270° .

then,

→ 5 + 270° (anticlockwise)

→ 5 + {(180° + 90°)anticlockwise}

→ (5 + 180° anticlockwise) + 90° anticlockwise

→ 11 (opposite) + 90° anticlockwise

→ 11 + 90° anticlockwise  

→ 11 + 3*30° anticlockwise

→ 11 - 3

→ 8 (Ans.)

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Answer 2

Answer:

where will the hand of a clock stop if Lacy's starts from 5and make 3/4 of a rotation anti-clock wise