Question

whether 231/2^2×5^2×7 will have a terminating or non terminting repeating expansion​

Answer 1

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Answer 2

Answer:

terminating

Step-by-step explanation:

(231)(5^2)7/2^2

if denominator can be written in the form (2^n)(5^n) then the is said to be a terminating repeated expansion

therefore the term can be written as:

(231)(5^2)(7)/(2^2)(5^0)