Question

whether 6 and -6 are roots of 36+y²=0​

Answer 1

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Consider the equation

$36 + {y}^{2} = 0 \: \: ..........(1)$

Putting y=6 in both sides of Equation (1) we get

$36 + {6}^{2} = 36 + 36 = 72 \neq \: 0$

So 6 is not a root of (1)

Putting y=-6 in both sides of Equation (1) we get

$36 + { - 6}^{2} = 36 + 36 = 72 \neq \: 0$

So - 6 is not a root of (1)

Hence - 6 & 6 are not root of (1)

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Answer 2

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