Which 2 numbers give 14400 on multiplying and 40 on adding?
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Answer:
20 + √(14000)¡ , 20 - √(14000)¡
Step-by-step explanation:
since there are no real roots of the eqn. the roots are imaginary
since sum of roots =40 =s
product of roots = 14400 =p
the roots are also roots of
x^2 -sx + p=0
or x^2 -40x + 14400=0
using quadratic formula
x= (40+- √[(40)^2 - (14400×4)])/2
this implies x= 20 +- √[-14000]
or x= 20 + √-14000 ,20- √-14000
since √-1 =¡
this implies x=20 + √(14000)¡ , 20 - √(14000)¡
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