Question

which al the two has a greater area
a rectangle af length 12 m and breadth
8 m or a square whose perimeter is
36 m​

Answer 1

Answer:

Area of rectangle $A_1$= 12 × 8 = 96 sq.m

again, perimeter of Square s = 4a, here a = side

a = s÷4= 36÷4 =9

Area of square $A_2$= $a^2$

= $9^2$ = 81

so $A_1$>$A_2$