Which algebraic identity can be used to factorise 4y2 – 4y+ 1?
Answers
Answered by
3
Answer:
Solution :
Given Quadratic expression is
4y² - 4y + 1
= ( 2y )² - 2 × 2y × 1 + 1²
= ( 2y - 1 )²
[ By algebraic identity,
a² - 2ab + b² = ( a - b )² ]
= ( 2y - 1 )( 2y - 1 )
Step-by-step explanation:
Answered by
1
Answer:
Step-by-step explanation:
(a-b)²=a²+b²-2ab
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