Question

Which among the following contains minimum number of hydrogen atoms? 300 g C2H 3 490 g H SO, 27 W 200 g NaOH 90 g H-O​

Answer 1

We have to find out the option among the following which contains minimum number of hydrogen atoms.

To find the no of hydrogen atoms in the given compound :  

first find the number of moles of compound which is found by the ratio of mass to the molar mass after that find the no of moles of hydrogen atoms in the given compound now finally multiply with Avogadro's number.

300g of CH₃OH,

molar mass of CH₃OH = 32 g

so no of moles of CH₃OH = 300/32 = 9.375

here, 4 atoms are present in one molecule of CH₃OH

∴ no of moles of H atoms in CH₃OH = 4 × 9.375 = 37.5

∴ no of H atoms in CH₃OH = 37.5 × N , where N is Avogadro's number.

490g of H₂SO₄

no of moles of H₂SO₄ = 490/98 = 5

here, 2 atoms are present in one molecule of H₂SO₄

so, no of moles of H atoms of H₂SO₄ = 2 × 5 = 10

∴ no of H aotms in H₂SO₄ = 10N

200g of NaOH

no of moles of NaOH = 200/40 = 5

here, one H atom is present in one molecule of NaOH

so the no of moles of H atom in NaOH = 5

∴ no of H atoms in NaOH = 5N

90g of H₂O

no of moles of H₂O = 90/18 = 5

here, 2 atoms are present in one molecule of H₂O

so the no of moles of H atoms in H₂O = 10

∴ no of H atoms in H₂O = 10N

Hence, it is clear that the minimum no of hydrogen atoms is present in the 200g of NaOH.

Answer 2

Answer:

option 4

Explanation: