Which among the following has maximum number of molecules?
Choose answer:
22 g CO2
40 g SO3
10 g CH4
20 g NO2
Answers
Answered by
1
Answer:
10 g ch4 is right
Explanation:
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Answered by
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no. of moles = 22 / [12+(2×16)]
of CO2 = 22 / 44
= 0.5
no. of moles = 40 / [32+(3×16)]
of SO3 = 40 / 80
= 0.5
no. of moles = 10 / [12+(1×4)]
of CH4 = 10 / 16
= 0.625
no. of moles = 20 / [14+(2×16)]
of NO2 = 20 / 46
= 0.435
no. of moles is directly proportional to no. of molecules
hence, 10g of CH4 has maximum no. of molecules.
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