which amongst the following will have more number of atoms? 1= 6.4 gram of sulphur, 2=9.3 of phosphorus [S=32,P=31]
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no of atoms of sulphur in 32g=1mole
no of atoms of sulpur in 6.4g=(1/32)*6.4
=6.4/32
=64/320=8/40=1/5mole......(1)
no of atoms of phosporus in 31g=1mole
no of atoms of phosporus in9.3g=(1*9.3)/31
=93/310=3/10...(2)
comparing (1) and (2)
2/10<3/10
So PHOSPHORUS HAVE MORE NO OF ATOMS
no of atoms of sulpur in 6.4g=(1/32)*6.4
=6.4/32
=64/320=8/40=1/5mole......(1)
no of atoms of phosporus in 31g=1mole
no of atoms of phosporus in9.3g=(1*9.3)/31
=93/310=3/10...(2)
comparing (1) and (2)
2/10<3/10
So PHOSPHORUS HAVE MORE NO OF ATOMS
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