Question

which aqueous solution has minimum freezing point ?

(a)0.01M NaCl

(b) 0.005M C2H5OH

(c) 0.005M MgI2

(d) 0.005M MgSO4

Answer 1

Answer: 0.01M NaCl

Explanation:

Answer 2

The aqueous solution of 0.01M NaCl has a minimum freezing point.

Explanation:

• The principle used is if the freezing point depression is minimum, the freezing point will be maximum and vice versa.
• Accordingly, the freezing point depression for given solution are calculated using the formula:

Δ$T_f = i \times K_f\times m$

Where:

i = Vant Hoff factor

m = Molarity

$K_f$ = 1.86

Freezing point depression for:

1. 0.01M NaCl:

Δ$T_f = i \times K_f\times m$

Δ$T_f = 2\times 0.01m \times 1.86$

Δ$T_f$ = 0.03

2. 0.005M $C_2H_5OH$

Δ$T_f = i \times K_f\times m$

Δ$T_f = 1\times 0.005 \times1.86$

Δ$T_f$ = 0.009

3. 0.005M $MgCl_2$

Δ$T_f = i \times K_f\times m$

Δ$T_f = 2.7\times 0.005\times 1.86$

Δ$T_f$ = 0.02

4. 0.005M Mg$SO_4$

Δ$T_f = i \times K_f\times m$

Δ$T_f = 2\times 0.005\times 1.86$

Δ$T_f$ = 0.01

• From the above calculation, as the Δ$T_f$ value of 0.01M NaCl is maximum, it has a minimum freezing point.

Learn more about such concept

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