Which are the factors of the expression 3x ^ 3 + 23x - 8 ?
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Answer:
Here,f(x)=3x3+2x2–3x–2
So, 3x+2=0⇒x=−2/3
Thus, remainder =f(−2/3)
=3(−2/3)3+2(−2/3)2–3(−2/3)–2
=−8/9+8/9+2–2
=0
Therefore, (3x+2) is a factor of f(x).
Now, performing division of polynomial f(x) by (3x+2) we get
Thus, 3x3+2x2–3x–2=(3x+2)(x2–1)=(3x+2)(x–1)(x+1)
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Answer:
3x of the characters a of 34.5 of the second number= 3o2
Step-by-step explanation:
T#Tyt of the number
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