Question

which are the two consecutive positive integers, sum of whose squares is 365


​

Answer 1

Step-by-step explanation:

let two consecutive positive integer be x and x+1

$x {}^{2} + (x + 1) = 365 \\ x { }^{2} + x - 182 = 0 \\ (x + 14)(x - 13) = 0 \\ x = 13 \\ x = - 14$

Answer 2

Answer:

Step-by-step explanation:the sum of two consecutive positive nor be 13 and 14

              so,    square of 13= 169

                                                    14=196

                                                    then sum=

                                                                      196+169=365