Question

Which are the zero of p(x) = ( x-1)(x-2) step to step please

Answer 1

Answer:

(0-1) (0-2)

(-1)(-2) =2

Answer 2

Given,

$\large \dag \: \: \: \bf{p(x) = (x - 1)(x - 2)}$

To find : Zeroes of p(x)

$<marquee>SOLUTION :⤵⤵ </marquee>$

On Equating p(x) with zero,

$\rm \longmapsto \: (x - 1)(x - 2) = 0 \\ \\ \bf = > (x - 1) = 0 \\ \bf = > \: \: \: \: \: x = 0 + 1 \\ \bf = > \: \: \: \: \: \: x = \red1 \\ \overline{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:} \\ \bf = > (x - 2) = 0 \\ \bf = > \: \: \: \: \: \: x = 0 + 2 \\ \bf = > \: \: \: \: \: \: x = \red2$

Hence,

• Zeroes of p(x) are 1 and 2.