Question

Which are the zeroes of p(x)=(x-1)(x-2)

Answer 1

Given

p(x) = (x-1)(x-2)

➪ p(x) = x² - 2x - x +2

➪ p(x) = x² - 3x + 2

For zeroes of p(x)

px) = 0

➪ x² - 3x + 2 = 0

By Splitting method

➪ x² - x - 2x + 2 = 0

➪ x(x - 1) - 2(x - 1) = 0

➪ (x - 2) (x - 1) = 0

➪ x = 2 , x = 1

∴ The zeroes of p(x) = 1, 2