Math, asked by agirlwithdoubts, 10 months ago

Which are the zeroes of p(x)=(x-1)(x-2):
A) 1,-2
B)-1,2
C) 1,2
D)-1,-2

Answers

Answered by VineetaGara
4

The Answer is C ) 1,2 i.e the roots of the given equation are 1 and 2.

1) According to fundamental theorem of Algebra The zeroes a and b of any equation are those which can represent the equation in the form of (x-a)(x-b)=0.

2) Here the equation is given as (x-1)(x-2)=0.

3) Therefore by fundamental Theorem of Algebra, the roots of equation are 1 and 2.

Answered by sohamd2019
2

Answer:

Step-by-step explanationThe Answer is C ) 1,2 i.e the roots of the given equation are 1 and 2.

1) According to fundamental theorem of Algebra The zeroes a and b of any equation are those which can represent the equation in the form of (x-a)(x-b)=0.

2) Here the equation is given as (x-1)(x-2)=0.

3) Therefore by fundamental Theorem of Algebra, the roots of equation are 1 and 2.

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