Math, asked by Anonymous, 11 months ago

Which are the zeroes of p(x)=(x-1)(x-2) (a) 1 -2 (b) -1 2 (c) 1 2 (d) -1 -2

Answers

Answered by pulakmath007
2

Answer:

The zeroes of p(x)=(x-1)(x-2) are (c) 1, 2

Step-by-step explanation:

For Which are the zeroes of p(x)=(x-1)(x-2) we get

(x-1)(x-2) = 0

x = 1,2

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