Question

which are the zeroes of p (x)=x^2-1​

Answer 1

Answer:

x=1

Step-by-step explanation:

given:-

p(x)=x²-1

To find zero of the given polynomial p(x)

putting p(x)=0

x²-1=0

x²=1

x=√1

x=1

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Answer 2

Answer:

$p(1) = {x}^{2} - 1 \\ \: \: \: \: \: \: \: \: \: \: = {1}^{2} - 1 \\ \: \: \: \: \: \: \: \: \: \: = 0 \\ p(-1) = { - 1}^{2} - 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 1 - 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 0$

1 and -1 are the zeroes of p(x)

Step-by-step explanation:

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