Question

which are the zeroes of p(x) =x^2 -2x -8:​

Answer 1

Answer:

x = -2 and x= 4

Step-by-step explanation:

as you already know you have to apply the method of splitting the middle term

x^2 - 2x - 8 =0

x^2 - 4x + 2x -8 = 0

x(x-4) + 2 (x-4) = 0

(x+2) (x-4) = 0

x+2 =0

x= -2

x - 4 = 0

x = 4