Question

which are the zeroes of p(x) =x^2 -2x -8:

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Answer 1

Answer:

p(x) = x² - 2x - 8

zero = -2, 4

Step-by-step explanation:

x²-2x-8

= x² - 4x + 2x - 8 (by splitting the middle term)

=x(x-4) + 2(x-4) (by taking x and 2 common)

= (x+2)(x-4)

zero of (x+2)

x+2 = 0

x= -2

zero of (x-4)

x-4 = 0

x = 4

zeroes of p(x) are (-2) and 4

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