Question

Which are the zeroes of p(x) = x^2 + 7x +12 ? *

1 point

4 , -3

-4 , 3

-4 , -3

4 , 3​

Answer 1

Answer:

your answer : -4 , -3

Step-by-step explanation:

x^2 + 7x + 12

x^2 + 4x + 3x + 12

x ( x + 4 ) + 3 ( x + 4 )

( x + 4 ) ( x + 3 )

x+4 = 0

x = -4

x + 3 = 0

x = -3

Answer 2

thank my answer

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