Question

Which are the zeroes of p(x) = x2-2x-8:
नेठ रिडिमां हि p(x) = x2-2x-8 रीमा मिढतां में।
p(x) = x2 -2x -8 के शून्यक कौन से हैं.
O. -2,-4
-2,4
O O
024
None of these/ टिपठां हिउँ वैप्टी ठग/ इनमें से कोई नहीं​

Answer 1

x²-4x+2x-8

=x(x-4)+2(x-4)

=(x+2)(x-4)

so, x=-2.x =4

Answer 2

Step-by-step explanation :

→ x² - 2x - 8 = 0

→ x² - 4x + 2x - 8 = 0

→ x ( x - 4 ) + 2 ( x - 4 ) = 0

→ ( x + 2 ) ( x - 4 ) = 0

→ x = -2 and x = 4

Required zeroes are -2 and 4.

More :-

This question can also be solved using quadratic formula which is x = -b ± √( b²- 4ac ) / 2a.

Here:

• x = roots of equation
• a = coefficient of x²
• b = coefficient of x
• c = constant term in equation

To find the discriminant of any quadratic equation, we have a formula D = b² - 4ac where D is the discriminant. It helps in finding out whether the roots of the equation are real or imaginary and if they are equal or distinct.

Nature of roots are classified as:-

Value of D ‎ ‎ ‎ ‎ ‎ ‎Nature of roots

‎ ‎ ‎0 ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎Two equal real roots

‎ ‎ ‎+ve ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ Two distinct real roots

‎ ‎ ‎-ve ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ No real roots