Question

Which are the zeroes of p(x)=x2+7x+12

Answer 1

Answer:

-4, -3

Step-by-step explanation:

The polynomial is x²+7x+12

a=1,b=7,c=12

Factors of x²+7x+12

=x²+4x+3x+12

=x(x+4)+3(x+4)

=(x+4)(x+3)

Zeroes of the polynomial

x²+7x+12 =0

(x+4)(x+3)=0

x= -4,-3

ZEROES = -4, -3

SUM OF ROOTS = -4-3=-b/a=-7/1

=> -7=-7

PRODUCT OF ROOTS= -4*-3=c/a

=> 12=12

Hope it helps

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