Which are the zeros of p(x) 6x sq-7x-3
Answers
Answered by
0
Step-by-step explanation:
6x^2 - 7x - 3 = 0
6x^2 +2x - 9x - 3 = 0
2x(3x + 1) - 3(3x + 1)
(2x -3) (3x + 1)
x = 3/2 or -1/3
Similar questions