Question

which are the zeros of p x = x2 - 1

Answer 1

${\pink{\bf{Hola!!}}}$

given:-

p(x)=x²-1

To find zero of the given polynomial p(x)

putting p(x)=0

x²-1=0

x²=1

x=√1

${\bold{\blue{\boxed{x=1}}}}$

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Answer 2

$\mathfrak{\huge{Answer:}}$

$\sf{Given:}$

p (x) = $\tt{x^{2} - 1}$

$\sf{Method:}$

To find the solution of these types of questions, try to simplify the given equation / information more and more. The more and more you simplify, the more simpler the answer will come.

=》 $\tt{x^{2} = 1}$

Do the square root on both the sides. You will get the answer.

=》 $\tt{x = \sqrt{1}}$

Since, the value of square root of 1 is also 1, we can write that :-

=》 x = 1

Thus, the value of x will be = 1

$\sf{Verification:}$

$\tt{1^{2} - 1 = 0}$

This will happen because the value of the square of 1 is also 1.

Hence $\huge{\bold{x =1}}$