Question

which are the zeros of PX is equals to x square - 1​

Answer 1

$\large{\implies{Answer}}$

$x {}^{2} - 1 = 0 \\ x {}^{2} = 1 \\ x = \sqrt{1} \\ x =1$

Verification :

$x {}^{2} - 1 = 0 \\ (1) {}^{2} - 1 = 0 \\ 1 - 1 = 0 \\ 0 = 0$

Answer 2

Answer:

Step-by-step explanation:

x²-1= (x+1)(x-1)

if p(x)=0

therefore,

(x+1)(x-1)=0

if (x+1)=0

x= -1

if x-1 =0

x=1

therefore the roots of

x²-1 are -1 and +1

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