Which are zeroes of p(x)=6x^2-7x-3 :-
(options mentioned in photo)
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6x²-7x-3 = 0
=> 6x²+9x-2x-3 = 0
=> 3x(2x+3)-1(2x+3) = 0
=> 3x-1 = 0 or 2x+3 = 0
=> x = 1/3 or x = -3/2
Answer: (d) none of these .
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the answer is option (d)
I think this is the answer...........I hope it helps you
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