Math, asked by Srynu2016, 10 months ago

Which are zeroes of p(x)=x^2+7x+12 :-
(options mentioned in photo)​

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Answers

Answered by allekeerthi13
1

Answer:

the answer is option (c)

I think this is the answer............I hope it helps you

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Answered by Anonymous
2

Answer:

p ( x ) = x^2 + 7x + 12

= x^2 + 4x + 3x + 12

= x ( x + 4 ) + 3 ( x + 4 )

= ( x + 4 ) ( x + 3 )

zeroes of p ( x ) = x^2 + 7x + 12

( x + 4 ) = x = -4

( x + 3 ) = x = -3

option c is correct..............

hope it helps you...........................

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