Which are zeroes of p(x)=x^2+7x+12 :-
(options mentioned in photo)
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1
Answer:
the answer is option (c)
I think this is the answer............I hope it helps you
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p ( x ) = x^2 + 7x + 12
= x^2 + 4x + 3x + 12
= x ( x + 4 ) + 3 ( x + 4 )
= ( x + 4 ) ( x + 3 )
zeroes of p ( x ) = x^2 + 7x + 12
( x + 4 ) = x = -4
( x + 3 ) = x = -3
option c is correct..............
hope it helps you...........................
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