Which are zeroes ofp(x)=6x sqare-7x-3
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Answer:
x=3/2;-1/3
Step-by-step explanation:
6x^2-7x-3=0
6x^2-9x+2x-3=0
3x(2x-3)+1(2x-3)=0
2x-3=0;3x+1=0
2x=3;3x=-1
x=3/2;x=-1/3
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