Question

Which are zeros of p(x) = 6x^7x-3)

Answer 1

Step-by-step explanation:

given :6x²+7x-3

6x²-2x+9x-3

2x(3x-1)+3(3x-1)=0

(2x+3) (3x-1)

2x+3=0 , 3x-1=0

x=-3/2 , x = 1/3