Question

Which atom loses two electrons from its outer
shell to form an ion?
A Calcium
B Carbon
с Chlorine
D Oxygen

Answer 1

Answer:

Option A. Calcium.

Explanation:

hope this helps

Answer 2

Answer: The correct option is (a). Calcium atom looses $2$ electrons and form an ion.

Explanation:

• The atomic number of Calcium is $20$ and its electronic configuration is $2,8,8,2$. To achieve the configuration of a noble gas, it loses $2$ electrons to form $Ca^{2+}$ ion.

• The atomic number of Carbon is $6$ and its electronic configuration is $2,4$. It shares its $4$ electrons and forms covalent bond.

• The atomic number of Chlorine is $17$ and its electronic configuration is $2,8,7$. To achieve the configuration of a noble gas, it gains $1$ electron to form $Cl^{-1}$ ion.

• The atomic number of Oxygen is $8$ and its electronic configuration is $2,6$. To achieve the configuration of a noble gas, it gains $2$ electrons to form $O^{2-}$ ion.

Therefore correct answer is option (A).

#SPJ2