Which can be used to describe an equivalent expression for (s Superscript 6 Baseline) Superscript negative 3?
Adding the exponents will create an equivalent expression.
Dividing the exponents will create an equivalent expression.
There are three factors of StartFraction 1 Over s Superscript 6 Baseline EndFraction.
There are three factors of StartFraction 1 Over s Superscript 3 Baseline EndFraction.
Answers
Given : (s^6)^-3
(s⁶)⁻³
To Find : Which can be used to describe an equivalent expression for (s^6)^-3
Adding the exponents will create an equivalent expression.
Dividing the exponents will create an equivalent expression.
There are three factors of 1/s^6.
There are three factors of 1/s^3.
Solution
(s⁶)⁻³ = s⁻¹⁸ ( ∵ (xᵃ)ᵇ = xᵃᵇ )
(s⁶)⁻³ = (s⁻⁶)³ ( 6 * - 3 = -6 * 3 = - 18)
s⁻⁶ = 1/s⁶ ( ∵ x⁻ᵃ = 1/xᵃ)
(s⁶)⁻³ = ( 1/s⁶)³
( 1/s⁶)³ = ( 1/s⁶) ( 1/s⁶) ( 1/s⁶)
Hence three factors of 1/s⁶.
Adding the exponents => (s⁶)⁻³ = s⁻³ ≠ s⁻¹⁸
Dividing the exponents => (s⁶)⁻³ = s⁻² ≠ s⁻¹⁸
There are three factors of 1/s^6. - CORRECT OPTION
There are three factors of 1/s^3. = (1/s³)(1/s³) (1/s³) = 1/s⁹ = s⁻⁹ ≠ s⁻¹⁸
Hence There are three factors of 1/s⁶ is equivalent expression for (s⁶)⁻³
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