which colour have minimum stopping potential?
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red is correct answer
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Short: particle energy is inversely proportional to their wavelength ("colours of light").
We don't talk about stopping power in terms of particles that do not have the capability to cause ionisation upset events in solids.
There are 2 causes of this:
photons of light from the far infrared to deep UV tend to interact with matter and get completely absorbedsome solids have properties of reflection and refraction (in that they alter the period & sign of the travelling wave), which, at the small scale of things, are the same side of a coinThus the particle-wave characteristics of a photon entering a solid are completely different from a photon exiting it; in effect, it may be the case that it is not the same photon at all if an absorption + re-emission process occurs. With beta & gamma radiation, my understanding is that we are concerned about how much of "that solid" till no significant detector signal strength is reached on the other side.
The general relationship that governs the energy of a photon is given by the de Broglie wavelength relationship,
λ=hcpcλ=hcpc, where:
h is the Planck constant
c is the speed of light in vacuum
and since the relativistic limit approximation of p=mcp=mc
We can also express this as:
E=hcλE=hcλ
Which means ~1.24eV corresponds to 1000nm.
We don't talk about stopping power in terms of particles that do not have the capability to cause ionisation upset events in solids.
There are 2 causes of this:
photons of light from the far infrared to deep UV tend to interact with matter and get completely absorbedsome solids have properties of reflection and refraction (in that they alter the period & sign of the travelling wave), which, at the small scale of things, are the same side of a coinThus the particle-wave characteristics of a photon entering a solid are completely different from a photon exiting it; in effect, it may be the case that it is not the same photon at all if an absorption + re-emission process occurs. With beta & gamma radiation, my understanding is that we are concerned about how much of "that solid" till no significant detector signal strength is reached on the other side.
The general relationship that governs the energy of a photon is given by the de Broglie wavelength relationship,
λ=hcpcλ=hcpc, where:
h is the Planck constant
c is the speed of light in vacuum
and since the relativistic limit approximation of p=mcp=mc
We can also express this as:
E=hcλE=hcλ
Which means ~1.24eV corresponds to 1000nm.
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