Question

which constant must be added and subtracted to solve the quadratic equation by the method of completing the square 9xsquare+3/4 x-√2=0​

Answer 1

Answer:

don't know this answer sorry

Answer 2

Answer:

Given quadratic equation

9x^2 - 3x/4 - 2 = 0

( 3x )^2 - 2 x 3x x 1/8 - 2 = 0

(3x)^2-2 x (3x) x(1/8) + (1/8)^2 - (1/8)^2

= 2 - -(1)

(3x - 1/8 )^2 = 2 - ( 1/8 )^2

(3x - 1/8 )^2 = 2 - 1/ 64

(3x - 1/8 )^2 = (128 - 1)/ 64

(3x - 1/8)^2 = 127/ 64

From (1)

Here we added and

subtracted

(1/8)^2 = 1/ 64 to solve the

quadratic

equation by the completing square.