Question

Which constant should be added and
subtracted to solve the quadratic equation
4x2 - V3x + 5 = 0 by the method of
completing the square?​

Answer 1

Answer:

$we \: have \\ 4x \sqrt{3x} - 5 = 0 \\ divide \: whole \: equation \: by \: 4 \\ therefore \: {x}^{2} - \frac{ \sqrt{3} }{4} x - \frac{5}{4} = 0 \\ therefore \: (x - \frac{ \sqrt{3} }{8} {)}^{2} - \frac{5}{4} = \frac{3}{64} \\ = 4(x - \frac{ \sqrt{3} }{8} {)}^{2} - 5 - \frac{3}{16} = 0 \\ therefore \: \frac{3}{16} must \: be \: added \: to \: make \: 4 {x}^{2} - \sqrt{3x} - 5 = 0 \\ a \: complete \: square$

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