Question

Which constants can be multiplied by the equations so one variable will be eliminated when the systems are added together? 5x + 13y = 232 12x + 7y = 218 The first equation can be multiplied by –13 and the second equation by 7 to eliminate y. The first equation can be multiplied by 7 and the second equation by 13 to eliminate y. The first equation can be multiplied by –12 and the second equation by 5 to eliminate x. The first equation can be multiplied by 5 and the second equation by 12 to eliminate x.​

Answer 1

Answer:

You can start off by distributing the x-variables and using the LCM of 5 and 12

5 = 5x1

12= 2x2x3

LCM: 1x2x2x3x5= 60

We could also determine the LCM of 13 and 7 (y-variables), since they are both prime numbers.  

13x7= 91

The LCM is 91.

Answer 2

$\huge\boxed{\mathcal\red{Answer : - }}$

$5x + 13y = 232. \\ 12x + 7y = 218.$

$The \: first \: equation \: can \: be \: multiplied$

$by –13 \: and \: the \: second \: equation$

$\: \: \: \: \: \: \: by 7 \: to \: eliminatey$