Which construment is uesd to demonstrate electrostatic shielding
Answers
Answer:
Shielding the inside from the outside. It is well known that no electric fields exist inside a hollow conductor, even if there are charges present outside. The conductor acts like an electrostatic shield. This is only true if the conductor is kept at a constant potential. Indeed, assuming electrostatic equilibrium and the concept of equipotential surface, one can argue by contradiction that there cannot be an electric field inside. Even though Gauss' law proves that it must be so, the nuances prevent many students from appreciating what's going on. Using a "segmented shield," one can demonstrate that electrostatic shielding doesn't work when the potential is not constant. When it is constant, the shielding effect arises from superposition of the field from the outside charge distribution and the opposing "back-field" of the hollow conductor. The "back-field" is directly observable in this demonstration.
(2) Shielding the outside from the inside. A charge inside a hollow conductor produces a charge distribution on the outer surface of the conductor, and this induced charge distribution creates an electric field outside the closed conductor. Again, Gauss' law tells us it must be so. A test charge (probe) positioned outside the conductor seems to be repelled by the charge inside the conductor no differently whether or not the conducting shield is there. Thus, electrostatic shielding does not work both ways. (Note that the field outside will depend on the shape of the shield and not in any way reflect the internal charge distribution. For example, if the shield is a metal sphere, the field outside will be Coulomb-like and radial. Not so if it's a box.) However, shielding the outside can be accomplished by grounding the conductor. This allows charges to flow (from ground) onto the conductor, producing an electric field opposite to that of the charge inside the hollow conductor. The conductor then acts like an electrostatic shield as a result of the superposition of the two fields.
Explanation:
Hope it helps you . Please mark my answer as brainliest.
